golangconf2019-challenge/README.md
Iskander (Alex) Sharipov 557775055a
Update README.md
2019-09-28 16:34:24 +03:00

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[travis-image]: https://travis-ci.org/GolangKazan/golangconf2019-challenge.svg?branch=master
[travis-url]: https://travis-ci.org/GolangKazan/golangconf2019-challenge
↶ Check to see a current winner<br>
[![Build Status][travis-image]][travis-url]
[GolangConf 2019](https://golangconf.ru/2019) challenge from and for [GolangKazan](https://golangkazan.github.io/) community!
The winner will get a free ticket to a conference.
## Get involved! Win a free ticket GolangConf!
How to participate:
1. Make a public post that contains a link to [this repository](https://github.com/GolangKazan/golangconf2019-challenge) with both `#GolangKazan` and `#GolangConf2019` hash tags ([example](https://twitter.com/GolangKazan/status/1177939214437994496)).
2. Fork this repository.
3. Add yourself in `challenge.go` file variable `gophers`.
4. Send a [Pull Request](https://help.github.com/en/articles/creating-a-pull-request) with your changes.
5. If CI tests will pass, your contribution will be merged.
6. When PR is merged, you're awesome and can potentially win a prize.
## How the winner is selected
We print winner after tests are finished.
Your pull request triggers a new CI build.
Inside that build logs, info line about the winner is printed.
When we'll stop this challenge, the last printed winner will be awarded.
Example (how "printed" winner may look like):
![](https://habrastorage.org/webt/kl/kk/k7/klkkk7zghbwmsuwefnaqxhyv3-y.jpeg)
<hr>
For a post there are several things to be considered:
* Post must survive until we stop the challenge and announce the winner.
* Account that does the announcement must have at least 10 followers/subscribers.
Possible sites that can be used for a public post: [vk](http://vk.com/), [twitter](http://twitter.com/), [instagram](https://www.instagram.com).<br>
Note that you can use other social network, channel.
<hr>
If you have any questions, feel free to ask them at https://t.me/GolangKazan channel.